63^2+216^2=x^2

Solution for 63^2+216^2=x^2 equation:

63^2+216^2=x^2

We move all terms to the left:

63^2+216^2-(x^2)=0

We add all the numbers together, and all the variables

-1x^2+50625=0

a = -1; b = 0; c = +50625;
Δ = b2-4ac
Δ = 02-4·(-1)·50625
Δ = 202500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{202500}=450$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-450}{2*-1}=\frac{-450}{-2}
=+225
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+450}{2*-1}=\frac{450}{-2}
=-225
$